cos²α = 1 – sin²α = 1 – 9/25 = 16/25 → |cos α| = 4/5 Kuadranti i dytë → cos α = –4/5 tg α = sinα / cosα = (3/5)/(-4/5) = –3/4
— please or describe it here, and I’ll be glad to help solve and explain it clearly. Matematika 11 Pegi Teste Te Zgjidhura --39-LINK--39-
Zgjidh ekuacionin: tg x = √3 për x ∈ [0, 2π) cos²α = 1 – sin²α = 1 –